Rotational Inertia in two cylinders

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SUMMARY

The discussion focuses on calculating the kinetic energies of two uniform solid cylinders, each with a mass of 1.25 kg and an angular velocity of 235 rad/s. The first cylinder has a radius of 0.18 m, while the second has a radius of 0.73 m. The moment of inertia (I) is calculated using the formula I = mr², yielding values of 0.050625 kg·m² for the smaller cylinder. The user initially miscalculated the kinetic energy, which is given by the formula KE = 0.5 * I * ω², and sought clarification on unit conversions and the correct application of angular velocity.

PREREQUISITES
  • Understanding of rotational dynamics
  • Familiarity with the moment of inertia formula (I = mr²)
  • Knowledge of kinetic energy in rotational motion (KE = 0.5 * I * ω²)
  • Basic proficiency in unit conversions, particularly radians
NEXT STEPS
  • Study the concept of rotational inertia in detail
  • Learn about the relationship between angular velocity and linear velocity
  • Explore the effects of radius on moment of inertia and kinetic energy
  • Review unit conversion techniques for angular measurements
USEFUL FOR

Physics students, mechanical engineers, and anyone interested in understanding the principles of rotational motion and energy calculations.

TheAce3317
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Calculate the kinetic energies of two uniform solid cylinders, each rotating about its central axis. They have the same mass, 1.25 kg, and rotate with the same angular velocity, 235 rad/s, but the first has a radius of 0.18 m and the second a radius of 0.73 m.

I got 12112188.868 for ω, and 0.050625 for I


I have been using I=mr^2, and .5*Iω^2



I plugged everything in without changing any units, and got 1906125390.62499825 for the small one, which i know to be wrong. Then I thought I remembered something my teacher said about multiplying the radians by 2pi, and then I plugged all the numbers back in and got another large number.
 
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nvm, ran out of time. getting help from my teacher tomorrow
 

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