Rotational Inertia: Solve for Acceleration of Suspended Masses

[annamae]

Homework Statement

Two masses are suspended from a pulley system. The pulley itself has a mass of .2kg, a radius of .015m, and a constant torque of .35Nm due to friction between the rotating pulley and its axle. What is the magnitude of acceleration of the suspended masses if m₁=.4kg and m₂ = .8kg?

Homework Equations

Torque=I(rotational inertia) * angular acceleration
I= 1/2* m * r²

The Attempt at a Solution

T=I*a
.35= (.5)(.2)(.015²)(a)
233.333=angular acceleration

233.333/.015=3.5
3.5=linear acceleration

What do I do with the masses?
Is all that above work right?

 

[cupid.callin]

T = Ia is for T(total) you have just taken T due to friction
also use the T due to tension in strings ...

and for masses find net acceleration using newon's laws and find tension in 2 strings ... then apply T=Ia

 

[annamae]

could you maybe explain that with a bit more detail, I am still not sure of what to do