How Do You Solve for Acceleration in a Two-Mass Pulley System?

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SUMMARY

The discussion focuses on solving for acceleration in a two-mass pulley system involving mass m1 (28.1 kg) and mass m2 (6.70 kg). A force of 231.3 N is applied to m1 at an angle of 29.5 degrees. The equations derived for the system include m1a = Fcos(theta) - T - uk*m1*g + uk*Fsin(theta) for m1 and m2a = T - m2*g for m2. Participants are struggling with the calculations, particularly in determining the tension (T) and the coefficient of friction (uk).

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Homework Statement



Mass m1=28.1 kg is on a horizontal surface, connected to mass m2= 6.70 kg by a light string as shown. The pulley has negligible mass and no friction. A force of 231.3 N acts on m1 at an angle of 29.5o.



Homework Equations




I can't seem to get the correct answer for this one.
I get this equation for the horizontal forces on m1:

m1a = Fcos(theta) -T -ukm1g +ukFsin(theta)

And this one for the vertical forces on m2:

m2a = T -m2g

I can combine these equations and solve for a, but that
doesn't seem to be working out for me. Any suggestions?


The Attempt at a Solution



I plugged in all of the numbers, but it does not seem to be working out
 
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Seems right to me. What is the coefficient of friction? What number do you get for a?
 
you posted this on lon capa too.. how did you get T ??
 

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