The angular acceleration of a solid sphere with a mass of 5 kg and a radius of 0.6 meters, when a force of 3 N is applied perpendicular to the radius, is calculated using the formula α = τ/I. The correct moment of inertia for a solid sphere is I = (2/5)MR², leading to an angular acceleration of 10 rad/sec². For a hollow sphere, the moment of inertia is I = (2/3)MR², which differs from that of a solid sphere. This distinction is crucial for accurate calculations in rotational dynamics.
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Sam Cepeda said:Homework Statement
. What is the angular acceleration if a force of 3 N is applied perpendicular to the radius of a 5 kg solid sphere that has a radius of 0.6 meters?
Homework Equations
= r x F
I = mr^2
The Attempt at a Solution
I used
tried solving for angular acce.
3N/(5kg)(0.6) =10rad/sec^2
Also, if the question had said "hollow sphere" would the moment of inertia be different..(2/3)mr^2 ?