# Rotational kinematics of a turntable

1. Nov 19, 2011

1. The problem statement, all variables and given/known data

An electric turntable 0.710 m in diameter is rotating about a fixed axis with an initial angular velocity of 0.230 rev/s. The angular acceleration is 0.887 rev/s^2.

A. Compute the angular velocity after a time of 0.192 s.

B. Through how many revolutions has the blade turned in this time interval?

C. What is the tangential speed of a point on the tip of the blade at time t = 0.192 s?

D. What is the magnitude of the resultant acceleration of a point on the tip of the blade at time t = 0.192 s?

2. Relevant equations

Any rotational kinematic.

3. The attempt at a solution

A.) I took the angular velocity 0.230 and multiplied it by 2pi which equals 1.445 rad/s.

I then plugged it into a kinematic equation, 1.445+(0.887*0.230)^2 = 2.56 rad/s = .400 rad/s.

This is right.

B.) The I used the distance rotational kinematic equation, 1.445 * 0.230 +.5(0.887)(0.230)^2 = 0.3558 rad. = 0.57 rev.

This is wrong. Need help.

C) To to find the tangential speed, I did 0.710 m * 2.56 rad/s = 1.82.

This is wrong. Need help.

D) Need help.

Thanks.

2. Nov 19, 2011

### dynamicsolo

On part (b), have you perhaps "plugged in" the initial angular velocity where the time interval 0.192 seconds belongs?

I think you have misled yourself because you have omitted a factor (and wrote another incorrectly) in the typing of your equation in part (A):

I believe that should be 1.445 + [(0.887*2*pi)^2] (0.192) = 2.56 rad/s . I agree with your result, but you didn't get it using what you've typed.

Last edited: Nov 19, 2011
3. Nov 19, 2011

### rock.freak667

Conversion is correct.

From what I gather, your formula is Ω = ω + (αω)2 ?

I am not following this line as that computation gives me 1.48 or so.

4. Nov 19, 2011

The angular velocity w = w0 + a*t where w0=0.23*2*Pi rad./s
also where 'a' = 0.887*2*Pi rad./s^2
At t=0.192, w(0.192) = 0.23*2*Pi + 0.887*2*Pi*0.192

On part B, I need to plug in time(0.192 s) where I plugged in initial angular velocity?

For, C, should i be using the radius of .355 m? Then multiply it by 2.56?

5. Nov 19, 2011

### rock.freak667

The formula is θ = ωt + ½αt2

You plugged in t as 1.445 and ω as 0.230, you need to plug in ω as 1.445 and t=0.192. Just makes sure α is in rad/s2

Yes that would be correct since you know that v = rω

6. Nov 20, 2011

Ok, thank you guys for all the help! much appreciated.

7. Nov 20, 2011

For part D.

I received the tangential acceleration by the change in speed of (2.56 rad/s)^2 multiplied by the radius of 0.355 m.