Rotational/Linear motion & friction

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    Friction Motion
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Homework Help Overview

The problem involves a 2.4 kg block on a 30° slope connected to a solid drum, with the goal of determining the coefficient of friction between the block and the slope as the block accelerates down the slope at 1.2 m/s².

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss drawing free-body diagrams and applying equations related to forces, tension, and torque. Questions arise regarding the role of the drum and its rotation axis, as well as the application of the work-energy theorem.

Discussion Status

The discussion is active, with participants exploring different approaches to the problem. Some guidance has been offered regarding the use of the work-energy theorem and the relationship between forces and torque. There is an ongoing exploration of how to relate acceleration to displacement and velocity.

Contextual Notes

Participants note the need to consider the effects of gravity and the specific setup of the drum's rotation, which may impact the analysis. There is mention of missing information regarding displacement or velocity in relation to the given acceleration.

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Homework Statement



A 2.4 kg block rests on a 30° slope and is attached by a string of negligible mass to a solid drum of mass 0.80 kg and radius 5.0 cm, as shown in Fig. 10.29. When released, the block accelerates down the slope at 1.2 m/s2. What is the coefficient of friction between block and slope?

Homework Equations



Ff=mu*N

a=alpha*r

Torque=I*alpha


The Attempt at a Solution



Ok the first thing I did was draw a free-body diagram of the block and the drum. I have Fnet=mg-Tension-mu*Fnormal then and set Tension=torque and got T=1/2*Mdrum*a and put that back into the original equation and solved for mu, but I didn't get the right answer. Is this even the right way to do this?
 
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Hi Nick_L! Welcome to PF! :smile:
Nick_L said:
A 2.4 kg block rests on a 30° slope and is attached by a string of negligible mass to a solid drum of mass 0.80 kg and radius 5.0 cm, as shown in Fig. 10.29. When released, the block accelerates down the slope at 1.2 m/s2. What is the coefficient of friction between block and slope?

I don't get it … what's the drum doing? :confused:

is it rotating on a fixed horizontal axis, with the string unwinding, or on a fixed vertical axis, or is it sliding down the hill on its base?
 
Here is the picture associated with the problem

12-47.gif
 
ok … rotating on a fixed horizontal axis, presumably with a frictionless axle, and with the string unwinding …

so use the work-energy theorem … work done = energy lost, using the mass of the object and the moment of inertia of the drum :wink:
 
Ok so I would have Ffriction*dcos(30)=1/2*massbox*v2+1/2I*omega2? If that's right it makes sense, but how would I find displacement or velocity when I only have the acceleration?
 
Nick_L said:
Ok so I would have Ffriction*dcos(30)=1/2*massbox*v2+1/2I*omega2? If that's right it makes sense, but how would I find displacement or velocity when I only have the acceleration?

(you left out gravity)

sorry, I missed the acceleration :redface:

in that case, just use F = ma and torque = Iα and slug it out! :smile:
 
Alright, thanks for the help :biggrin:
 

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