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Homework Help: Dynamics ramp and friction. Finding angle?

  1. Jul 26, 2017 #1
    1. The problem statement, all variables and given/known data
    A 3.0 kg block is released from the top of a rough ramp of length 2.0m and accelerates down the ramp at 1.6m/s^2. If a force of kinetic friction of 10 N acts on the block, what is the angle of the ramp.

    2. Relevant equations
    ff=(mu??? I don't have that symbol HAHA) muFn

    3. The attempt at a solution

    if Fnet=ma..... then

    then take inverse to get theta..

    Now what! answer should be 30 but when I put in the values I get 10 degrees. help please
  2. jcsd
  3. Jul 26, 2017 #2
    What are you plugging in for ff here? This may be where the mistake is.
  4. Jul 26, 2017 #3
    I just thought because the question states that there is a kinetic force of friction and acceleration, there are unbalanced forces, meaning you need an Fnet. Therefore I plug in Ff kinetic to complete that idea.
  5. Jul 26, 2017 #4
    Oh, right. I missed that they gave you the force of friction in the problem.
    You have a sign mistake here, it should be
    because the vectors for friction and gravity point in opposite directions.
  6. Jul 26, 2017 #5


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    When editing a post, there is a line of symbols above the text area. If you click on the Σ symbol a couple of lines of special characters will appear below the text area. Click those as necessary.
    Please also use the subscript and superscript as appropriate (x2, X2). Later on you might advance to using LaTeX.
    That depends on the sign convention chosen. If Britt chooses the same direction as positive for all forces and accelerations (a good approach often) then the equation for parallel to the plane is $$\Sigma F=F_{f}+F_{g}=ma$$
    The negative sign comes in when values are plugged in. If downslope is positive then Ff=-10N, Fg=+mg sin(θ).
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