Rotational Motion angular speed

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SUMMARY

The discussion centers on calculating the final angular speed of a wheel rolling down a ramp. The wheel starts with an initial angular speed of 2.0 rad/s and experiences a constant angular acceleration of 2.5 rad/s² over a period of 8 seconds. The correct final angular speed at the bottom of the ramp is 22 rad/s, as derived from the equation ω_final = ω_initial + α * t. A common mistake noted was miscalculating the final speed, which led to an incorrect answer of 20 rad/s.

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Homework Statement



11. A wheel with an angular speed of 2.0 rad/s is rolling on a horizontal surface and starts down a ramp. It rolls down the ramp with a constant angular acceleration of 2.5 rad/s2. If it takes 8 s to reach the bottom of the ramp, what is the final angular speed of the wheel at the bottom?

a. 20 rad

*b. 22 rad/s

c. 18 rad/s

d. 25.5 rad/s


Homework Equations



acentripetal=Δω/t

The Attempt at a Solution



I plugged into the equation initial velocity as 2.0rad acceleration as 2.5 and time as 8 and solved for final velocity which have me 20 rad/s the answer key says its 22
 
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The final angular speed consists of the initial angular speed plus the amount it accelerated on the ramp.

Pertinent equation is: omega final = omega initial + alpha *time
 
Ohh i did my math wrong sory
 

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