1. The problem statement, all variables and given/known data A shaft is turning at 65.0 rad/s at time zero. Thereafter, its angular acceleration is given by α = -10 rad/s 2 - 5t rad/s 3 where t is the elapsed time. (a) Find its angular speed at t = 3.00 s. (b) How far does it turn in the 3.00 s seconds? t=3 seconds wi= 65.0 rad/s α = -10 rad/s 2 - 5t rad/s 3 2. Relevant equations Wf=Wi+αt where α is the angular acceleration 3. The attempt at a solution since α = -10 - 5t (1) at t= 3 seconds by substitution in (1): α= -25 rad/s2 From Kinematic equation: wf=wi+αt wf=65-25(3)= -10 rad /s I found a different answer in the solutions so please tell me why my answer is incorrect.