Rotational Motion of speed and a car

Click For Summary

Homework Help Overview

The problem involves the rotational motion of a car's wheels as the vehicle decelerates from 80 km/h to 55 km/h, completing 55 rotations during this process. The diameter of the wheels is given as 1 meter, and participants are tasked with finding the angular acceleration and the time taken to stop the car under the same deceleration.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the relationship between linear and angular motion, using equations related to angular velocity and acceleration. There is discussion about the correct interpretation of angular displacement and the use of radius versus diameter in calculations.

Discussion Status

Some participants have provided guidance on correcting the approach to calculating angular acceleration and displacement. There is an ongoing examination of the values used in the calculations, particularly regarding the initial and final angular velocities. Multiple interpretations of the problem are being explored, particularly concerning the angular displacement and the application of the relevant equations.

Contextual Notes

Participants are working under the constraints of textbook answers that differ from their calculations, leading to questions about significant figures and the correct application of formulas. There is a focus on ensuring that the correct values are used for radius and angular displacement.

kalupahana
Messages
31
Reaction score
0

Homework Statement


When a car is decelerating it's speed reduces from 80 km/h to 55 km/h. In this time the wheels of car complete 55 rotations. The diameter of the wheel is 1m.
Find the
1) angular acceleration of the car.
2) time taken to stop the car if it continued in same deceleration.


Homework Equations


v = rω
ω21 = ω20 + 2αθ
ω1 = ω0 + αt

Any equation regarding motion can be used to do this.
I used above three

The Attempt at a Solution


55 km/h = 15.2 m/s
80 km/h = 22.2 m/s

v = rω
I got ω = v/r from it. So
ω0 = 22.2 m/s
ω1 = 15.2 m/s

Then I used this equation to find angular acceleration
ω21 = ω20 + 2αθ

15.22 = 22.22 + 2 x 55 x π x α

-261.8 = 2 x 22/7 x 55 x α

α = -0.75 rad/s2

ω1 = ω0 + αt
can be use to find the time taken to stop

0 = 15.2 - 0.75t
t = 15.2/0.75 = 20.26 s


But in the textbook the answers are given as -1.5 rad/s2 for angular acceleration and 20 sec for time taken to stop. But I got other things.
Please help me to complete this.
Thnx
 
Physics news on Phys.org
Assuming that they're actually asking for angular acceleration of each wheel, not the car - you seem to have erred in determining the angular displacement, as well as using the diameter of the wheel (instead of radius). Fixing those two errors gives the correct -1.5 rad/s^2 answer.

Your second part was done correctly, but you used the wrong values (found in the first part). Also - don't forget significant figures!
 
What should I take as Angular displacement.
It makes 55 rotations during that decelerating time. One rotation is 2П. Then 55 rotations means 110П rotations.
When I use like this i got 0.34 rad/s^2.

You said that second part is correct. But how.
I used the data gain by the first part.(The angular acceleration as 0.75).
If it was incorrect 20 sec could not be get.

The angular acceleration -1.5 rad/s^2 can be gain by 0.75 x 2. Please explain me how did you reached to the answer.
 
110pi rotations is right. But, you it appears that you still haven't corrected your angular velocities by using radius, as opposed to diameter. Using the equations you posted as "Relevant Equations" gives you the right answers.
 
that means the radius is 1/2m.
Then velocities are come like 15.2 x 2 & 22.2 x 2.
Ok I understand. I'll try from it
 

Similar threads

  • · Replies 20 ·
Replies
20
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
2
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
2
Views
3K
Replies
1
Views
2K
  • · Replies 18 ·
Replies
18
Views
8K
  • · Replies 2 ·
Replies
2
Views
6K