Car Rounding Curve: Acceleration Calculation with C=2piR

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A car rounding a level curve with a radius of 100 meters at a constant speed of 30 m/s experiences centripetal acceleration despite maintaining constant speed. The distinction between speed and velocity is crucial, as velocity involves direction, which changes while the car turns. The initial confusion regarding the radius and circumference was clarified, emphasizing the need to understand the concept of acceleration in circular motion. Resources for further learning on this topic were recommended, as the subject had not been covered in class. Understanding these principles is essential for solving similar physics problems effectively.
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Homework Statement


A car rounds a level curve of radius 100 meters at a constant speed of 30 m/s.
What is the magnitude of the acceleration of the car?

Homework Equations


C = 2piR

The Attempt at a Solution


I calculated the circumference as 628m. Besides that, I'm ignorant of the procedure to solve this.
 
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Austin Gibson said:
1. A car rounds a level curve of radius 100 meters at a constant speed of 30 m/s.
What is the magnitude of the acceleration of the car?

Homework Equations


C = 2piR[/B]

The Attempt at a Solution


I calculated the radius as 628m. Besides that, I'm ignorant of the procedure to solve this.[/B]
What have you learned about cars going around curves? Do they accelerate?
The radius is given as 100 m. You cannot claim that it is 628 m. Please pay attention to what you are doing.
 
I intended to type "circumference" instead of "radius." This is the first time I encountered this type of question. My initial estimation was the acceleration would be zero if the speed is constant.
 
Austin Gibson said:
I intended to type "circumference" instead of "radius." This is the first time I encountered this type of question. My initial estimation was the acceleration would be zero if the velocity is constant.
The speed is constant but not the velocity. Velocity has direction which in this case is changing. Speed has no direction. The speedometer in a car indicates the speed but it does not indicate in which direction the car is moving; that's why it's called a "speedometer".

Does the question make more sense now? This problem must be related to a section in your textbook, notes or material covered in class. What is the acceleration when something goes around in a circle?
 
Yes, I understand the distinction now because acceleration is the change in velocity rather than speed. Unfortunately, we never reviewed this subject in class. Gravity is vertically holding the car to the earth. That seems irrelevant if it's horizontally turning a corner.
 
Austin Gibson said:
Yes, I understand the distinction now because acceleration is the change in velocity rather than speed. Unfortunately, we never reviewed this subject in class. Gravity is vertically holding the car to the earth. That seems irrelevant if it's horizontally turning a corner.
Since you didn't review this in class, you should review it on the web. Just do a web search for the title of this thread and you will see a wealth of useful information out there, videos, tutorials, worked out examples, etc. Happy hunting.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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