Runge-Lenz Vector: Calculating Magnitude & Direction

  • Thread starter Thread starter samjohnny
  • Start date Start date
  • Tags Tags
    Vector
Click For Summary
SUMMARY

The discussion focuses on the calculation of the magnitude and direction of the Runge-Lenz vector in the context of orbital mechanics. Participants confirm that the Runge-Lenz vector is a constant of motion, derived from the differentiation of the vector with respect to time, yielding a value of zero. The vector is equivalent to the eccentricity vector, and its calculation requires knowledge of initial conditions such as distance and velocity. The dot product of the Runge-Lenz vector with the position vector is suggested as a method to explore the relationship between the vector and the object's motion in various orbital shapes.

PREREQUISITES
  • Understanding of the Runge-Lenz vector in classical mechanics
  • Familiarity with vector calculus and differentiation
  • Knowledge of orbital mechanics, including circular and elliptical orbits
  • Basic concepts of momentum and velocity in physics
NEXT STEPS
  • Study the derivation and properties of the Runge-Lenz vector in detail
  • Learn how to calculate the eccentricity vector for different orbital shapes
  • Explore the implications of the dot product in vector analysis
  • Investigate the relationship between initial conditions and orbital trajectories
USEFUL FOR

Students and professionals in physics, particularly those focusing on classical mechanics and orbital dynamics, will benefit from this discussion. It is especially relevant for those studying celestial mechanics and the mathematical foundations of motion in gravitational fields.

samjohnny
Messages
83
Reaction score
1

Homework Statement



Please find it attached.

Homework Equations



95de2fe45c8ce9deef85438d31928c57.png

233599c315ed09e65711c7f9410eab4f.png

676dc21daca293b822638428a5ea3c2e.png


The Attempt at a Solution



For the first part of the question I managed to show that the vector is a constant of the motion by differentiating it with respect to time and showing that it yields a value of zero.

As for the second part where I need to calculate the magnitude and direction of the vector then I'm not sure how to go about doing that explicitly. I know that the way vector is defined is such that it is equivalent to the eccentricity vector and so for the circle part it would necessarily be equal to zero. But to show that explicitly I'm not to sure. Any ideas?
 

Attachments

  • Runge-lenz.JPG
    Runge-lenz.JPG
    40.2 KB · Views: 699
Physics news on Phys.org
samjohnny said:

Homework Statement



Please find it attached.

Homework Equations



95de2fe45c8ce9deef85438d31928c57.png

233599c315ed09e65711c7f9410eab4f.png

676dc21daca293b822638428a5ea3c2e.png


The Attempt at a Solution



For the first part of the question I managed to show that the vector is a constant of the motion by differentiating it with respect to time and showing that it yields a value of zero.

As for the second part where I need to calculate the magnitude and direction of the vector then I'm not sure how to go about doing that explicitly. I know that the way vector is defined is such that it is equivalent to the eccentricity vector and so for the circle part it would necessarily be equal to zero. But to show that explicitly I'm not to sure. Any ideas?
Hi,

First of all, notice that the Rung-Lenz Vector could be written by velocity of the particle, because momentum divided my mass is equal to velocity, and K is a constant. Obviously, it is necessary to know initial conditions of the particle, so assume that we know the initial distance and initial velocity, and therefore, the Runge-Lenz Vector (I show this with A). Let me show the particle position vector's with R. Now, calculate Dot Product of A and R in two different ways; in the first path, consider the A has its initial value, but in the second way, put its definition expression. Hence, by some calculation, you can find the R in terms of angle (from a specific axis.)
 
Kiarash said:
Hi,

First of all, notice that the Rung-Lenz Vector could be written by velocity of the particle, because momentum divided my mass is equal to velocity, and K is a constant. Obviously, it is necessary to know initial conditions of the particle, so assume that we know the initial distance and initial velocity, and therefore, the Runge-Lenz Vector (I show this with A). Let me show the particle position vector's with R. Now, calculate Dot Product of A and R in two different ways; in the first path, consider the A has its initial value, but in the second way, put its definition expression. Hence, by some calculation, you can find the R in terms of angle (from a specific axis.)

Thank you for the reply. Would it not be the case that, by dotting the Runge Lenz vector with R, the resultant expression would describe motion of the object? I'm not clear on what relation this would have to finding the magnitude/direction of the vector in the case of circular, elliptical etc orbits.
 
samjohnny said:
Thank you for the reply. Would it not be the case that, by dotting the Runge Lenz vector with R, the resultant expression would describe motion of the object? I'm not clear on what relation this would have to finding the magnitude/direction of the vector in the case of circular, elliptical etc orbits.
 

Attachments

  • IMG_20150316_004617.jpg
    IMG_20150316_004617.jpg
    37.7 KB · Views: 503

Similar threads

Replies
1
Views
809
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
6K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
3
Views
1K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 25 ·
Replies
25
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K