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A Running coupling of the Higgs potential

  1. Sep 27, 2016 #1
    Why is the coupling constant of the Higgs potential not a constant, but is a running constant?

    In other words, ##\lambda (h) \sim \lambda_{0} - \frac{y_{t}}{16\pi^{2}}\text{ln}\big(\frac{h^{2}}{m^{2}}\big) + \frac{\lambda_{0}^{2}}{16\pi^{2}}\text{ln}\big(\frac{h^{2}}{m^{2}}+\cdots##,

    where ##\lambda_{0}## is the bare coupling and ##y_{t}=\frac{m_{t}}{VEV}##, ##m_{t}## is the mass of the top quark and VEV is the HIggs vacuum expectation value?
     
  2. jcsd
  3. Sep 27, 2016 #2

    vanhees71

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    Science Advisor
    2016 Award

    Look for "renormalization group equation".
     
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