Undergrad Rydberg Equation: Physics and Beyond

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The Rydberg equation is still relevant in physics, particularly for hydrogen atoms, but its applicability is limited to specific cases. While it provides accurate results for hydrogen, it fails in more complex scenarios, as detailed in the linked Wikipedia article. Calculating orbital energy levels in such cases requires a deeper understanding of quantum mechanics, which is beyond the scope of casual discussion. For comprehensive insights, consulting a quantum mechanics textbook is recommended. The Rydberg equation remains a foundational concept, but its limitations must be acknowledged.
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Is Reydberg equation still valid and use?
I saw that rydberg equation used for hydrogen atom,so does it still acceptable for world of physics or it just dinied like bohr model?
 
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Iceking20 said:
I saw that rydberg equation used for hydrogen atom

Where did you see this?
 
Iceking20 said:
does it still acceptable for world of physics

The Wikipedia article you linked to explains in which cases the formula gives correct results and in which cases it does not.
 
PeterDonis said:
The Wikipedia article you linked to explains in which cases the formula gives correct results and in which cases it does not.
So what is the way to calculating orbital energy level?
 
Iceking20 said:
So what is the way to calculating orbital energy level?

Do you mean for cases where the Rydberg formula does not give correct results? That is a much more complicated subject which cannot be dealt with adequately in a PF discussion thread. You should consult a textbook on QM.
 
Time reversal invariant Hamiltonians must satisfy ##[H,\Theta]=0## where ##\Theta## is time reversal operator. However, in some texts (for example see Many-body Quantum Theory in Condensed Matter Physics an introduction, HENRIK BRUUS and KARSTEN FLENSBERG, Corrected version: 14 January 2016, section 7.1.4) the time reversal invariant condition is introduced as ##H=H^*##. How these two conditions are identical?

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