I am trying to calculate the Lyman-alpha wavelengths of photons emitted from different hydrogen-like atoms such as deuterium and positive helium ion(adsbygoogle = window.adsbygoogle || []).push({}); ^{4}He^{+}, using the relation 1/λ = R*|1/n_{i}^2 - 1/n_{f}^2|, where R is the Rydberg constant and n_{i}and n_{f}are integer numbers corresponding to the initial and final energy levels, which, for Lyman-alpha wavelength, are 2 and 1, respectively. The expression for Rydberg constant is R = m_{e}/(4πħ^{3}c)*(e^{2}/4πε)_{0}^{2}.

My question is: what changes in these two expressions when we are dealing with different hydrogen-like atoms?replace electron mass m_{e}with new reduced mass μ? atomic number Z (but it is not included in any of the two expressions)?

Any help will be appreciated!

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# I Hydrogen Atom Photon Emission Wavelength Formula

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