S = 12t and S = 490t^2 What do they mean?

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Homework Help Overview

The discussion revolves around two equations representing displacement as a function of time: S = 12t and S = 490t^2. Participants express confusion regarding the meaning of these equations and their implications in a physics context.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants attempt to understand the equations by relating them to common mathematical forms and considering their implications in terms of motion. Questions about unit analysis and the nature of the motion described by each equation are raised.

Discussion Status

Some participants have offered guidance on interpreting the equations and suggested performing unit analysis. There is ongoing exploration of the implications of the equations in terms of physical motion, with various interpretations being discussed.

Contextual Notes

Participants mention studying the topic in both physics and math, indicating a need for clarity on how the equations relate to physical movement and mathematical representation.

Indranil
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1. The problem statement, all variables, and given/known data
1. S = 12t, where S = displacement ant t = time (in seconds)
2. S = 490t^2, where S = displacement and t = time (in seconds)
What do the two equations mean here? I don't understand what they want to mean here. I am confused.
Could you draw the graphs in support of the two equations above?

Homework Equations


1. S = 12t, where S = displacement ant t = time (in seconds)
2. S = 490t^2 where S = displacement and t = time (in seconds)

The Attempt at a Solution


What I only know here S = displacement and t = time in seconds
 
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Think about the equations in terms of x and y (S being x and t being y). Then think about the common forms you are aware of ( y = mx +b, y=ax^2). I think they want you to try to verbally explain the equations. As this happens, this happens. You can easily draw the graphs using existing graphing knowledge which I assume you have.

You can check if you have the graphs right by putting the equations into a graphing calculator (desmos probably).
 
lekh2003 said:
Think about the equations in terms of x and y (S being x and t being y). Then think about the common forms you are aware of ( y = mx +b, y=ax^2). I think they want you to try to verbally explain the equations. As this happens, this happens. You can easily draw the graphs using existing graphing knowledge which I assume you have.

You can check if you have the graphs right by putting the equations into a graphing calculator (desmos probably).
Still, I don't understand what you mean. Could you make your point easier, please?
 
Indranil said:
Still, I don't understand what you mean. Could you make your point easier, please?
It would help if you could give me some context. Are you studying this for physics? math? graphing?

I can help you accordingly, since I would understand what the question wants you to answer.
 
Indranil said:
1. The problem statement, all variables, and given/known data
1. S = 12t, where S = displacement ant t = time (in seconds)
2. S = 490t^2, where S = displacement and t = time (in seconds)
What do the two equations mean here? I don't understand what they want to mean here. I am confused.
Could you draw the graphs in support of the two equations above?

Do a unit (dimensional) analysis...

For 1.: If t is in seconds and S is in meters what must the units associated with the 12 be?

For 2.: likewise if t is in seconds and S is in meters what are the units associated with the 490?
 
lekh2003 said:
It would help if you could give me some context. Are you studying this for physics? math? graphing?

I can help you accordingly, since I would understand what the question wants you to answer.
Sir, I am studying this for physics and math
 
CWatters said:
Do a unit (dimensional) analysis...

For 1.: If t is in seconds and S is in meters what must the units associated with the 12 be?

For 2.: likewise if t is in seconds and S is in meters what are the units associated with the 490?
For 1. It would be 12 seconds and for 2. it would 490 seconds^2
If I am wrong here please correct me
 
Indranil said:
1. The problem statement, all variables, and given/known data
1. S = 12t, where S = displacement ant t = time (in seconds)
2. S = 490t^2, where S = displacement and t = time (in seconds)
What do the two equations mean here? I don't understand what they want to mean here. I am confused.
Could you draw the graphs in support of the two equations above?

Homework Equations


1. S = 12t, where S = displacement ant t = time (in seconds)
2. S = 490t^2 where S = displacement and t = time (in seconds)

The Attempt at a Solution


What I only know here S = displacement and t = time in seconds
Indranil said:
Sir, I am studying this for physics and math
Since you're studying physics as well as math, the equations model a physical situation where something is moving.

In equation 1, each second that elapses, the displacement s changes by 12 units. What sort of motion is implied here? IOW, is the object accelerating, decelerating, or moving at constant speed?

In equation 2, what is the displacement at t = 0 seconds? At t = 1 second? At t = 2 seconds? Is the object acclerating, decelerating, moving at constant speed, not moving at all?

Since you are also studying math, it might be helpful to sketch the graphs of these two equations, with the t-axis horizontal and the s-axis vertical.
 
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Indranil said:
For 1. It would be 12 seconds and for 2. it would 490 seconds^2
If I am wrong here please correct me

No that's not correct.

For 1...

S = 12t
so
12 = S/t

S is in meters and t in seconds so the 12 is actually 12 m/s (meters per second) which makes it a velocity.

In other words eqn 1 is of the form

Displacement = Velocity * time

Can you try something similar for 2.
 
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Indranil said:
Sir, I am studying this for physics and math

I think you just have to describe the movement of the object following the path defined by the equation. "As the object displaces by S, time will progress proportionately". Try and think of a description of the particle. Draw a time VS displacement graph and try and follow the particle. Try and visualize.

P.S. No need to call me Sir, I am in high school.
 

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