S.H.M Homework - Why Consider One Mass Only?

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Homework Help Overview

The discussion revolves around a problem involving simple harmonic motion (S.H.M) with two masses connected by a spring. Participants are exploring the reasoning behind considering one mass in the analysis of the system's motion.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to understand the implications of analyzing the motion of each mass separately while questioning the treatment of the system as a whole. There are discussions about the relationship between displacement, force, and mass in the context of the spring's behavior.

Discussion Status

The discussion is active, with participants raising questions about the assumptions made in the analysis. Some guidance has been offered regarding the separation of the masses in the analysis, but there is still uncertainty about the correct application of mass and force equations.

Contextual Notes

Participants are grappling with the definitions of mass and displacement in the context of the spring system, and there is a focus on the implications of holding one mass stationary while stretching the other. The original poster's confusion about the equations used suggests a need for clarity on the system's dynamics.

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Homework Statement



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The Attempt at a Solution


I know how to show ,but I don't understand why we consider one mass only

[PLAIN][PLAIN]http://b.imagehost.org/0195/questionb.jpg
 
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That looks like two masses connected by a spring. You describe the motion of each mass (with respect to the center) separately, but they are definitely connected.
 
Doc Al said:
That looks like two masses connected by a spring. You describe the motion of each mass (with respect to the center) separately, but they are definitely connected.

they strecthed at the same time.
so

ma =-kx
a=-(k/m) x
ma=-kx
a= -(k/m)x

but I don't know how to combine as

a=-(2k/m)x

I think it should be a=-(2k/2m)x = -(k/m)x
 
I believe that instead of stretching both, you could hold one down and stretch the other twice as far.
 
Feldoh said:
I believe that instead of stretching both, you could hold one down and stretch the other twice as far.

That means

ma = -k(2x)?
a=(-2k/m)x ?

I am doubt why ma is used instead of 2ma ?
the whole mass of system is 2m ?
 
mysqlpress said:
they strecthed at the same time.
so

ma =-kx
a=-(k/m) x
ma=-kx
a= -(k/m)x
If x is the displacement of each mass, the amount of stretch in the spring is 2x.
 
Doc Al said:
If x is the displacement of each mass, the amount of stretch in the spring is 2x.
but why should we use

ma=-2kx
but not
2ma=-2kx ?
since there are two bob with mass m..
 
mysqlpress said:
but why should we use

ma=-2kx
but not
2ma=-2kx ?
since there are two bob with mass m..
Because we are analyzing the motion of each mass separately:

What's the mass? m
What's the stretch of the spring? 2x
What's the force on each mass? -2kx
 
Doc Al said:
Because we are analyzing the motion of each mass separately:

What's the mass? m
What's the stretch of the spring? 2x
What's the force on each mass? -2kx

Thanks Doc Al.
you do help me a lot :devil:
 

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