feerrr
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why sup x in [a,b] |Pn(x) - f(x) | < ϵ , Pn(x)=a0+a1x+...+anx^n
why f(x)-ϵ<Pn(x)<f(x)+ϵ
why f(x)-ϵ<Pn(x)<f(x)+ϵ
The discussion revolves around the mathematical concept of approximating a continuous function \( f \) on the interval \([a, b]\) using polynomial functions \( P_n(x) \). Participants explore the implications of the condition \( \sup_{x \in [a,b]} |P_n(x) - f(x)| < \epsilon \) and its relation to proving that \( f(x) = 0 \) on the interval.
Participants express uncertainty regarding the use of the supremum condition to prove \( f(x) = 0 \). There is no consensus on whether the Weierstrass approximation theorem is necessary or if an alternative approach exists.
Participants acknowledge the need for additional assumptions, such as the boundedness of \( f \) on \([a,b]\), which may affect the validity of their arguments.
What I suggest is to look up the theorem on line and find a proof using it. It's still not easy.feerrr said:no i don't know the Weierstrass approximation theorem .
can i show that f(x)=0 without using the Weierstrass approximation theorem ? i need some help