MHB S6.12.11 Find an equation of the sphere

  • Thread starter Thread starter karush
  • Start date Start date
  • Tags Tags
    Sphere
karush
Gold Member
MHB
Messages
3,240
Reaction score
5
$\tiny{s6.12.11}\\$
\begin{align}
&\textsf{(a) Find an equation of the sphere with center (1, -4, 3) and radius 5. }\\
&(x - 1)^2 +( y +4)^2 +(z - 3 )^2 = 5 ^2=25 \\
\\
&\textsf{(b) What is the intersection of this sphere with the
xz-plane?.}\\
&\textit{assume it is an equation of a circle for the intersection}\\
\end{align}
$\textit{}$
 
Last edited:
Physics news on Phys.org
For a sphere of radius $r$ and centered at $(a,b,c)$, we have:

$$(x-a)^2+(y-b)^2+(z-c)^2=r^2$$

What is the value of $y$ for all points in the $xz$-plane?
 
In the $xz$-plane, we have $y=0$...:D
 

Similar threads

Replies
2
Views
2K
Replies
1
Views
1K
Replies
8
Views
2K
Replies
4
Views
2K
Replies
3
Views
1K
Replies
1
Views
1K
Back
Top