MHB S6.12.11 Find an equation of the sphere

  • Thread starter Thread starter karush
  • Start date Start date
  • Tags Tags
    Sphere
Click For Summary
The equation of the sphere with center (1, -4, 3) and radius 5 is derived as (x - 1)² + (y + 4)² + (z - 3)² = 25. For the intersection of this sphere with the xz-plane, where y = 0, the equation simplifies to (x - 1)² + 16 + (z - 3)² = 25. This leads to the equation (x - 1)² + (z - 3)² = 9, representing a circle in the xz-plane with a radius of 3 centered at (1, 0, 3). The discussion emphasizes the relationship between the sphere's equation and its intersection with the coordinate planes. Understanding these geometric relationships is crucial for solving similar problems in three-dimensional space.
karush
Gold Member
MHB
Messages
3,240
Reaction score
5
$\tiny{s6.12.11}\\$
\begin{align}
&\textsf{(a) Find an equation of the sphere with center (1, -4, 3) and radius 5. }\\
&(x - 1)^2 +( y +4)^2 +(z - 3 )^2 = 5 ^2=25 \\
\\
&\textsf{(b) What is the intersection of this sphere with the
xz-plane?.}\\
&\textit{assume it is an equation of a circle for the intersection}\\
\end{align}
$\textit{}$
 
Last edited:
Physics news on Phys.org
For a sphere of radius $r$ and centered at $(a,b,c)$, we have:

$$(x-a)^2+(y-b)^2+(z-c)^2=r^2$$

What is the value of $y$ for all points in the $xz$-plane?
 
In the $xz$-plane, we have $y=0$...:D
 

Similar threads

Replies
2
Views
2K
Replies
1
Views
1K
Replies
4
Views
2K
Replies
8
Views
2K
Replies
3
Views
2K
Replies
1
Views
1K