Sacrificial Anodes and Oxidation Number of KMnO4

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SUMMARY

The discussion centers on the corrosion behavior of an iron nail wrapped in zinc and the oxidation states of potassium permanganate (KMnO4). It is established that zinc, being more reactive than iron, serves as a sacrificial anode, thus reducing the corrosion of the iron nail. However, some oxidation of iron may still occur due to incomplete coverage. Regarding KMnO4, potassium has an oxidation state of +1, manganese is +7, and oxygen is typically -2, which collectively balance to zero in the compound.

PREREQUISITES
  • Understanding of sacrificial anodes in corrosion prevention
  • Basic knowledge of oxidation states in chemistry
  • Familiarity with the properties of potassium permanganate (KMnO4)
  • Knowledge of chemical bonding and electron transfer
NEXT STEPS
  • Research the principles of sacrificial anodes and their applications in corrosion protection
  • Study the oxidation states of transition metals, particularly in complex compounds
  • Explore the chemical properties and reactions of potassium permanganate (KMnO4)
  • Learn about the exceptions to common oxidation state rules, especially for oxygen
USEFUL FOR

Chemistry students, materials scientists, and professionals involved in corrosion engineering or chemical analysis will benefit from this discussion.

Procrastinate
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1. I have a question regarding an iron nail wrapped with zinc. The question asks me "Is it correct to say that corrosion did not take place in the nail wrapped with zinc? Explain."

I am not sure whether this is correct but I know that that zinc is more reactive than iron and will thus be more likely to oxidise than iron. However, as it is more likely, there will be some iron which will oxidise since not all of the iron has been cloaked by the zinc.
Is this correct and best explanation? I am not absolutely sure.
----------------------

2. KMnO4. O = -2 but how would I figure out what K and Mn is then? Apparently K is +1 and Mn is +7 but I don't know why. Could anyone please explain? I know they have to add up to zero.
 
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Procrastinate said:
KMnO4. O = -2 but how would I figure out what K and Mn is then? Apparently K is +1 and Mn is +7 but I don't know why. Could anyone please explain? I know they have to add up to zero.

Manganate has variable oxidation states, and it's dependent on the environment it's in. Potassium, as you said, has an oxidation state of +1; which I assume you are just expected to know. I again assume the same applies to Oxygen, its oxidation state is invariably -2. From these constants, you can deduce the oxidation state of Manganate.

Discalimer: I can not be held accountable for the accuracy of this post. Someone more knowledgeable will hopefully verify, or correct, as appropriate.:wink:
 
nobahar said:
I can not be held accountable for the accuracy of this post. Someone more knowledgeable will hopefully verify, or correct, as appropriate.:wink:

You are in general right, although in some compounds oxygen is not -2. But as a first approximation -2 is OK.

More on oxidation numbers calculation.

Please note that oxidation numbers are just an accounting device, they don't reflect any measurable property of atoms.

--
 
Borek said:
You are in general right, although in some compounds oxygen is not -2. But as a first approximation -2 is OK.
Thanks Borek.
 

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