Sample spaces having equally likely outcomes

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SUMMARY

The discussion centers on calculating the probability of obtaining exactly k heads when flipping a coin n times, specifically using the binomial coefficient. For n=3 and k=2, the number of favorable outcomes is given by the formula $$\binom{n}{k}$$, which equals 3 in this case. The correct outcomes for k=2 are identified as (h, h, x), (h, x, h), and (x, h, h), confirming that there are three combinations where exactly two heads appear.

PREREQUISITES
  • Understanding of binomial coefficients, specifically $$\binom{n}{k}$$
  • Basic probability concepts related to equally likely outcomes
  • Familiarity with combinatorial counting methods
  • Knowledge of the notation for heads (h) and tails (x) in probability scenarios
NEXT STEPS
  • Study the properties of binomial distributions and their applications
  • Learn about combinatorial proofs and counting techniques in probability
  • Explore the concept of sample spaces in probability theory
  • Investigate more complex probability problems involving multiple events
USEFUL FOR

This discussion is beneficial for students of probability theory, educators teaching combinatorial methods, and anyone interested in understanding the fundamentals of calculating probabilities in discrete scenarios.

blob84
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If we flip a coin n-times,
what is the probability of the event $$A= \left \{there \space are \space k \space head \right \}$$.
I should find the number of elements of A,
the book says that is $$\binom{n}{k}$$ but for $$n=3$$ and $$k=2$$, all the possible outcomes are:
$$A= \left \{(h, h,h), (h, h, x), (h, x, h), (x, h, h) \right \}$$, where the position of h or x is the k-flip.
How to find this number?

PS. h is head.
 
Last edited:
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hi blob84! :smile:

i'm sorry, i don't understand this at all :redface:

your example seems to be k = 3, not n = 3, and i don't understand what those four outcomes are :confused:

can you explain again?​
 
k is the number of the head in A, int the example k = 2, any vector of A has at least two head.
you flip a coin n-times, so if n = 3 you flip the coin 3 times, the problem is to count the number of vectors in A.

PS. h is head.
 
Last edited:
blob84 said:
int the example k = 2, any vector of A has at least two head.

ah, now i see what you meant :smile:

no, if k = 2, there must be exactly 2 heads

so the possible outcomes are

1: xxx k = 0 (0 heads)

3: xxh xhx hxx k = 1 (1 head)

3: xhh hxh hhx k = 2 (2 heads)

1: hhh k = 3 (3 heads)​
 
yes only 2 head, oh my god!
Thanks.
 

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