Big-Daddy
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So in SI units all I have to do with the kinetic energy term, bracketed T_n, is replace it with this:
- \sum^M_{A=1} ({\frac{h^2 \cdot m_e}{2 \cdot m_A} \cdot \nabla_A^2})
Where m_e is the mass of an electron, m_A is the mass of nucleus A and h (sorry I couldn't find h bar but that's what I meant) is the reduced Planck constant.
And put that into the second Hamiltonian and I would have created a complete SI unit version of the first?
- \sum^M_{A=1} ({\frac{h^2 \cdot m_e}{2 \cdot m_A} \cdot \nabla_A^2})
Where m_e is the mass of an electron, m_A is the mass of nucleus A and h (sorry I couldn't find h bar but that's what I meant) is the reduced Planck constant.
And put that into the second Hamiltonian and I would have created a complete SI unit version of the first?