Schwarzchild metric - rescaled coordinates

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The discussion focuses on the rescaling of coordinates in the Schwarzschild metric as presented in Alan Lightman's General Relativity problems. The standard form of the Schwarzschild metric is given by the equation d{s^2} = - (1 - 2M/r)d{t^2} + (1 + 2M/r)d{r^2} + r^2d{\Omega^2}. The rescaled form, which simplifies the metric to d{s^2} = - (1 - 2M/r)d{t^2} + (1 + 2M/r)(d{x^2} + d{y^2} + d{z^2}), is derived through a specific transformation of the radial coordinate, r = \tilde{r} (1 + M/2\tilde{r})^2. This transformation facilitates the understanding of the metric in Cartesian coordinates.

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Schwarzschild metric - rescaled coordinates

Hi,

I've been working through a problem (no. 14 in ch. 9) of Alan Lightman's book of GR problems. I can't understand one of the results that are stated without proof. Basically it amounts to a rescaling of coordinates.

I know that to first order in [tex]{\textstyle{M \over r}} \ll 1[/tex] (weak gravitational field), the standard Schwarzschild metric can be written

[tex]d{s^2} = - (1 - {\textstyle{{2M} \over r}})d{t^2} + (1 + {\textstyle{{2M} \over r}})d{r^2} + {r^2}d{\Omega ^2}[/tex]

in units where [tex]G = c = 1[/tex], and where [tex]d{\Omega ^2} = d{\theta ^2} + {\sin ^2}\theta d{\phi ^2}[/tex].

Lightman states that, in an "appropriate" coordinate system, the Schwarzschild metric (again to lowest order in [tex]{\textstyle{M \over r}} \ll 1[/tex]) can be written

[tex]d{s^2} = - (1 - {\textstyle{{2M} \over r}})d{t^2} + (1 + {\textstyle{{2M} \over r}})(d{x^2} + d{y^2} + d{z^2})[/tex],

where [tex]{r^2} = {x^2} + {y^2} + {z^2}[/tex].

I've been pulling my hair out trying to derive Lightman's form from the standard form I gave above. Apparently it's just a simple rescaling of the radial coordinate but I've had no luck. Any help would be appreciated!

Thanks in advance.
 
Last edited:
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Indeed, for this problem it's convenient to introduce a re-scaling ##r \rightarrow \tilde{r}## which satisfies ##r = \tilde{r} (1+M/2\tilde{r})^2##, which can also be re-arranged for ##1-2M/r = (1-M/2\tilde{r})^2/(1+M/2\tilde{r})^2##. Take the derivation,\begin{align*}
dr = (1+M/2\tilde{r})(1-M/2\tilde{r}) d\tilde{r}
\end{align*}Consider the classic Schwarzschild metric\begin{align*}
g &= -(1-2M/r) dt^2 + (1-2M/r)^{-1} dr^2 + r^2 d\Omega^2 \\ \\
&= - \dfrac{(1-M/2\tilde{r})^2}{(1+M/2\tilde{r})^2} dt^2 + \dfrac{(1+M/2\tilde{r})^2}{(1-M/2\tilde{r})^2} dr^2 + r^2 d\Omega^2 \\ \\
&= - \dfrac{(1-M/2\tilde{r})^2}{(1+M/2\tilde{r})^2} dt^2 + (1+M/2\tilde{r})^4 d\tilde{r}^2 + \tilde{r}^2 (1+M/2\tilde{r})^4 d\Omega^2 \\ \\
&= - \dfrac{(1-M/2\tilde{r})^2}{(1+M/2\tilde{r})^2} dt^2 + (1+M/2\tilde{r})^4 \left\{ d\tilde{r}^2 + \tilde{r}^2 d\Omega^2 \right\}
\end{align*}To first order in ##M/\tilde{r}##, one has simply\begin{align*}
g = (1-2M/\tilde{r}) dt^2 + (1+2M/\tilde{r})\{ d\tilde{r}^2 + \tilde{r}^2 d\Omega^2 \}
\end{align*}Defining new Cartesian-ish coordinates ##(x,y,z) = (\tilde{r} \sin{\theta} \cos{\phi}, \tilde{r} \sin{\theta} \sin{\phi}, \tilde{r}\cos{\theta})## puts the metric into this familiar form\begin{align*}
g = (1-2M/\tilde{r}) dt^2 + (1+2M/\tilde{r})\{ dx^2 + dy^2 + dz^2 \}
\end{align*}
 
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