Coordinate singularity in Schwarzschild solution

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Homework Help Overview

The discussion revolves around the Schwarzschild solution in general relativity, specifically addressing the nature of a singularity at a certain radius in the context of black hole metrics. The original poster is tasked with demonstrating that this singularity is a coordinate singularity by treating a time coordinate as an angular coordinate.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the interpretation of the singularity at ##r=0## and whether it should actually be at ##r=2m##. There is also inquiry into the implications of treating ##\tau## as an angular coordinate and what that entails for the metric.

Discussion Status

There is an ongoing exploration of the problem statement and the nature of the singularity. Some participants have pointed out potential errors in the problem setup, while others are seeking clarification on the implications of the coordinate transformation suggested.

Contextual Notes

Participants note that the metric presented differs from the standard Schwarzschild metric, raising questions about the validity of the original problem statement. There is also an emphasis on the need for the original poster to demonstrate some attempt at a solution as per forum guidelines.

Confused Physicist
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Hi! I have the following problem I don't really know how to approach. Could someone give me a hand?

The line element of a black hole is given by: ds^2=\Bigg(1-\frac{2m}{r}\Bigg)d\tau ^2+\Bigg(1-\frac{2m}{r}\Bigg)^{-1} dr^2+r^2\Big(d\theta ^2+\sin^2(\theta)d\phi ^2\Big)

It has an apparent singularity at ##r=0##. By making ##\tau## an angular coordinate, show that this singularity is a coordinate singularity (not physical) and find the period of ##\tau## that makes it possible. (consider expanding the metric functions about ##r=2m##).

Thanks for the help!
 
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Confused Physicist said:
The line element of a black hole

Note that this is not the usual Schwarzschild metric; there is no minus sign in front of the first term on the RHS. (If there were, the question would not make sense because ##\tau## would not be able to be treatd as an angular coordinate.)
 
@Confused Physicist I have moved this thread to the homework forum. You will need to at least show some attempt at a solution. You could start by taking the hint in the parenthetical in the OP.
 
Confused Physicist said:
It has an apparent singularity at ##r=0##. By making ##\tau## an angular coordinate, show that this singularity is a coordinate singularity

Are you sure the problem statement says ##r = 0## and not ##r = 2m##?
 
PeterDonis said:
Are you sure the problem statement says ##r = 0## and not ##r = 2m##?

Thanks PeterDonis, I will post my future questions in the homework forum. I've been trying to squeeze my head around it, but I haven't posted my attempt because I literally don't have a decent one.

Yes, the problem says ##r=0##, but you're right. I believe it's a mistake and it should say ##r=2m##.
 
Last edited:
PeterDonis said:
Note that this is not the usual Schwarzschild metric; there is no minus sign in front of the first term on the RHS. (If there were, the question would not make sense because ##\tau## would not be able to be treatd as an angular coordinate.)

What does it mean to treat ##\tau## as an angular coordinate? Is it a specific change of variable?
 
Confused Physicist said:
What does it mean to treat ##\tau## as an angular coordinate?

It means it only covers the range ##0## to ##2 \pi## instead of ##- \infty## to ##+ \infty##.
 

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