Scipy/numpy 2D array: how to define with a function?

[Dunhausen]

I want to make a matrix of values as so:

F(0,0) . . . F(1,n)
.
.
.
F(n,1) . . . F(n,n)

I could of course do it like this

list=[]
for i in range(0,n):
     for j in range(0,n):
     list.append(F(i,j))
a=array(list)
a.reshape(n,n)

But I am curious if there is a more elegant way to build an array with the rule Element i,j = F(i,j) ?

When working with 1-d arrays, I am accustomed to their savvy nature eliminating all need for 'for loops' in my code.

 

[story645]

a = numpy.empty((n+1,n+1))
for i in range(0,n):
    for j in range(0,n):
        a[i,j] = F(i,j)

or

i,j = numpy.meshgrid(range(0,n), range(0,n))
a = F(i,j)

 

[Dunhausen]

That is excellent! Thank you. :)

 

[story645]

Also, didn't have chance to edit, but range(n) generates the same list as range(0,n), if you want to be slightly more concise.