Seagull Mass from Tension on Telephone Wire

Click For Summary
SUMMARY

The discussion centers on calculating the mass of a seagull perched on a telephone wire that sags 43 cm between two poles 15 m apart, with a tension of 50 N in the wire. The equilibrium of forces acting on the seagull is analyzed using Newton's First Law, where the tension in the wire acts at angles to the horizontal. Participants emphasize the importance of drawing a free body diagram to visualize the forces and apply trigonometric principles to determine the angles involved, ultimately leading to the calculation of the seagull's weight and mass.

PREREQUISITES
  • Understanding of Newton's First Law of Motion
  • Basic knowledge of trigonometry for angle calculations
  • Familiarity with free body diagrams
  • Concept of equilibrium in physics
NEXT STEPS
  • Study the principles of equilibrium in static systems
  • Learn how to construct and interpret free body diagrams
  • Explore trigonometric functions and their applications in physics
  • Investigate the relationship between tension, weight, and angles in physics problems
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators looking for practical examples of equilibrium and tension in real-world scenarios.

ova5676
Messages
29
Reaction score
0

Homework Statement


A seagull lands on a telephone wire midway between two poles 15 m apart. The wire (assume weightless) sags by 43 cm. If the tension in the wire is 50 N what is the mass of the seagull?

Homework Equations


Ftotal = mass x acceleration
Ftotal = F1 + F2, etc.
Fg = mass x gravity

The Attempt at a Solution



I do not even know where to start. The seagull is on a wire but I'm not sure where the force of tension lies. Is it directed to both the left and the right of the seagull? I know that Fg and the normal force cancel out I think. And what role do the distances here play? Can anyone lend me a hand?
 
Physics news on Phys.org
Anyone there?
 
The wire and bird are in equilibrium, so Newton 1 applies. Draw a sketch. Yes, the tension acts in the rope and pulls on it both left and right and above the horizontal at an angle you can find from trig and at the given tension on both sides. The gull's weight acts down. Draw a free body digram of the bird, use Newton 1, and solve for the weight and then solve for the mass.
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 7 ·
Replies
7
Views
5K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
9
Views
8K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 2 ·
Replies
2
Views
7K
Replies
10
Views
3K
Replies
22
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
8K