Selection Rules (Time Dependent Perturbation Theory)

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SUMMARY

The selection rules for matrix elements in Time Dependent Perturbation Theory are defined by the conditions on quantum numbers. Specifically, the matrix element $$\langle n',l',m'|X|n,l,m\rangle$$ equals zero unless the changes in angular momentum quantum numbers satisfy $$\Delta l = l' - l$$ and $$\Delta m = m' - m$$, where $$\Delta l$$ and $$\Delta m$$ are constants dictated by the operator $X$. For the position operator, these constants are $$\Delta l = \pm 1$$ and $$\Delta m = \pm 1$$, as outlined in Shankar's text.

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Homework Statement
Suppose that the system is a single spinless particle of mass $$M$$ and charge $$e$$ in a central Coulomb potential and the quantum numbers of the initial state are labeled $$|n, l, m>$$ in the usual way. It is subject to perturbation with magnetic field $$ B(t) = B_0e ^{−λt}$$ pointing in the x direction, which adds a term $$eL_xB(t)/(2Mc)$$ to the Hamiltonian. Find the quantum number selection rules for allowed transitions to a different state.
Relevant Equations
$$[L_x,X]=0$$
I suppose my question is, since X commutes for H, does this mean that the selection rules are $$<n',l',m'|X|n,l,m>=0$$ unless $$l'=l\pm 1$$ and $$m'=m\pm 1$$, as specified in Shankar?
 
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No, that's not correct. The selection rules for the matrix element of any operator $X$ are given by $$\langle n',l',m'|X|n,l,m\rangle=0$$ unless $$l'-l=\Delta l$$ and $$m'-m=\Delta m$$ where $\Delta l$ and $\Delta m$ are constants depending on the particular operator $X$. In the case of the position operator, $\Delta l=\pm 1$ and $\Delta m=\pm 1$.
 

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