Self Adjoint and Anti-Self Adjoint questoin

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SUMMARY

Any normal linear transformation T can be expressed as the sum of a self-adjoint transformation T1 and an anti-self-adjoint transformation T2, such that T = T1 + T2 and T1 commutes with T2. The self-adjoint transformation is defined as T1 = (T + T*) / 2, while the anti-self-adjoint transformation is defined as T2 = (T - T*) / 2. This decomposition leverages the properties of normal transformations, which satisfy the condition = for all vectors a and b.

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  • Understanding of normal linear transformations
  • Familiarity with self-adjoint and anti-self-adjoint operators
  • Knowledge of inner product spaces
  • Basic linear algebra concepts
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  • Study the properties of normal linear transformations in detail
  • Learn about self-adjoint and anti-self-adjoint operators in linear algebra
  • Explore the implications of the decomposition T = T1 + T2 in various applications
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Mathematicians, linear algebra students, and anyone studying operator theory will benefit from this discussion, particularly those interested in the properties of normal transformations and their decompositions.

Alupsaiu
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I'm having trouble showing that any normal linear transformation T is the sum of a self-adjoint transformation T1 and anti-self adjoint linear transformation T2, (so T=T1+T2) so that T1 and T2 commute. Anti-self adjoint being <Ta,b>=-<a,Tb>.
Specifically I'm not sure how to use the information of T being normal.
Any help is appreciated, thank you.
 
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Hi Alupsaiu! :smile:

What about this standard trick:

[tex]T=\frac{T+T^*}{2}+\frac{T-T^*}{2}[/tex]
 
...Moments like these I feel so small...haha thanks a bunch
 

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