Semiclassical descriptions of atom-light interaction

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SUMMARY

The discussion focuses on the semiclassical description of atom-light interaction, specifically the Hamiltonian formulation involving a free atom and a classical electromagnetic (EM) field. The full Hamiltonian is expressed as H = (H_0 + p^2/2m) + (H_V + H_E) + H_D, where H_E represents the energy density of the classical field. The classical Hamiltonian for the electromagnetic field is given by H = ½(E² + B²), and the transition to quantum mechanics is achieved through the radiation gauge, leading to a Hamiltonian expressed in terms of the vector potential. The quantum aspect is introduced by relating the creation and annihilation operators to the number operator, N(k).

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  • Knowledge of the Jaynes-Cummings model in quantum optics
  • Proficiency in Fourier transforms and their application in quantum mechanics
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  • Research the driven Jaynes-Cummings model for insights into atom-light interactions
  • Study the radiation gauge in quantum electrodynamics for a deeper understanding of vector potentials
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Physicists, quantum mechanics students, and researchers in quantum optics seeking to understand the interaction between atoms and classical electromagnetic fields.

Niles
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Hi

Say I want to describe the interaction between a free atom atom and a classical EM field. The full Hamiltonian for the problem must be
<br /> H = (H_0 + p^2/2m) + (H_V + H_E) + H_D <br />
where H0 denotes the internal levels of the atom, HV the vacuum field, HE the energy density of the classical field and HD the dipole interaction.

My question is regarding HE. I have never seen it written explicitly and have not been able to find a reference where they do so. How would one write this? Is it QM-version of something similar to Poyntings vector?Niles.
 
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The Hamiltonian for a classical drive is something along the line of

<br /> E(e^{-i\omega t}a^\dagger+e^{i \omega t} a)<br />

I would suggest you look up some info about the driven Jaynes-Cummings model
 
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The usual form for the classical Hamiltonian for the electromagnetic field is the energy density, H = ½(E2 + B2). The easiest way to get to the quantum form is to use the radiation gauge, Φ = 0 and ∇·A = 0, allowing H to be written in terms of the vector potential as H = ½((A·)2 + (∇ x A)2).

Now Fourier transform, A = ∫d3k/√(2ω) ∑ε(k)[a(k)e-ik·x + a*eik·x], where ε(k) are polarization vectors. In terms of a(k) the Hamiltonian reduces to H = ∫d3k ω ∑a*(k)a(k). This is still classical.

Quantum mechanics comes in when you now say that a*(k)a(k) = ħ N(k) where N(k) is the number operator.
 
Ah, I see. Thanks for taking the time to explain that. I will study your reply in depth.

Best wishes,
Niles.
 

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