Separable Differential Equation dy/dz

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SUMMARY

The discussion focuses on solving the separable differential equation dy/dz = ycosx/(1+y^2) with the initial condition y(0) = 1, as presented in Stewart's Calculus, 6th Edition, section 10.3, problem 12. The solution involves integrating both sides, leading to the equation ∫(1+y^2)dy/y = ∫cosx dy, which simplifies to sinx + C. Participants seek clarification on whether to apply integration by parts for the integral of the product.

PREREQUISITES
  • Understanding of separable differential equations
  • Familiarity with integration techniques, including integration by parts
  • Knowledge of trigonometric functions and their integrals
  • Basic concepts of initial value problems
NEXT STEPS
  • Study the method of solving separable differential equations
  • Learn about integration by parts and its applications
  • Explore trigonometric integrals and their properties
  • Review initial value problems in differential equations
USEFUL FOR

Students studying calculus, particularly those tackling differential equations, as well as educators seeking to clarify integration techniques and initial value problem solutions.

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Homework Statement


dy/dz = ycosx/(1+y^2), y(0) = 1

Stewart 6e, 10.3 # 12

Homework Equations





The Attempt at a Solution


∫(1+y^2)dy/y = ∫cosxdy
-------------- = sinx + C

How do I find the integral of this product? Do I use integration by parts?
 
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BarackObama said:
∫(1+y^2)dy/y = ∫cosxdy
-------------- = sinx + C

How do I find the integral of this product? Do I use integration by parts?

Go for the obvious

(1 + y2)/y = … ? :smile:
 

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