Separable differential equations question

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SUMMARY

The discussion centers on solving a separable differential equation related to caloric intake and weight change. The equation presented is dW/dt = (1/3500) * (C - 17.5W), where C represents daily caloric intake and W denotes weight in pounds. This equation models the rate of change of weight based on the difference between caloric intake and calories burned. Understanding this equation is crucial for solving the subsequent parts of the problem.

PREREQUISITES
  • Understanding of differential equations, specifically separable equations.
  • Knowledge of basic calculus concepts such as derivatives and integrals.
  • Familiarity with the concept of proportionality in mathematical modeling.
  • Basic understanding of caloric balance and its impact on weight management.
NEXT STEPS
  • Study the method of solving separable differential equations.
  • Learn about the application of initial conditions in differential equations.
  • Explore the concept of exponential growth and decay in relation to weight change.
  • Investigate the implications of caloric intake on weight management strategies.
USEFUL FOR

Students studying differential equations, health professionals interested in weight management, and anyone looking to understand the mathematical modeling of caloric balance.

makaveli7
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How do I solve this? I can't seem to get part a and thus any of the other parts...

Any help would be appreciated... Thanx! :cool:
 
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You haven't shown any work at all so I'm not going to say much: If you take in C calories a day and burn 17.5 calories per pound (so that if your weight is W pounds you burn 17.5W calories) then your "excess in calories" is C- 17.5W calories. Write an equation that says dW/dt is proportional to that.
 
would it be dW/dt = (1/3500) * (C - 17.5*W) ?
 
Last edited:

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