Two consecutive numbers from 1,2,3.....n are removed A.M of remaining numbers is 105/4. Find n and those numbers removed .
n = 50
those numbers are 7 and 8
The Attempt at a Solution
I solved this question like a few weeks ago but now it escaped my brain I have no idea how .. and I am so annoyed now you know how it feels right?
Ok so heres what I got
The A.M of the total numbers would be
n(n+1) / 2 / n
that gives (n+1)/2
now what we get after removing the numbers
let the numbers be x and x+1
therefore their sum = 2x+1
now A.M after removing numbers
n(n+1)/2 - (2x+1) / (n-2) = 105/4
heres one I am not able to figyre out another relation PLease help somebody