Sequence satisfying a condition for all n

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Homework Statement



Suppose that a sequence {s_n} of positive numbers satisfies the condition s_(n+1) > αs_n for all n where α > 1. Show that s_n → ∞

My teacher mentioned something about making it into a geometric sequence and taking the log. I'm just confused.

Homework Equations





The Attempt at a Solution

 
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You can start with s2 > as1. Now what about s3? Can you compare it to s2 and s1? Continue...
 
StarTiger said:

Homework Statement



Suppose that a sequence {s_n} of positive numbers satisfies the condition s_(n+1) > αs_n for all n where α > 1. Show that s_n → ∞

My teacher mentioned something about making it into a geometric sequence and taking the log. I'm just confused.

Homework Equations





The Attempt at a Solution

So [itex]s_2> a s_n[/itex], [itex]s_3> a s_2> a(a s_1)= a^2 s_1[/itex], [itex]s_4> a s_3> a(a^2 s_1)= a^3 s_1[/itex]. So [itex]s_n>[/itex] a to what power times [itex]s_1[/itex]? What does that have to do with a "geometric sequence"?
 
If [tex](s_n)[/tex] is a sequence and the limit [tex]\lim_{n \to \infty}|s_{n+1} / {s_n}| = L[/tex] exists and [tex]L < 1[/tex], then [tex]\lim s_n[/tex] converges. If not, what do you think happens?