Series Convergence: Ratio Test & Lim. n→∞

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SUMMARY

The discussion focuses on the convergence of the series $$\sum_{n=1}^{\infty}\frac{{n}^{10}}{{2}^{n}}$$ using the Ratio Test. The limit to evaluate is $$L=\frac{1}{2}\lim_{n\to\infty}\frac{(n+1)^{10}}{n^{10}}$$, which simplifies to $$\frac{1}{2}$$ after applying the limit properties. The conclusion is that since $$L < 1$$, the series converges definitively.

PREREQUISITES
  • Understanding of series convergence tests, specifically the Ratio Test.
  • Familiarity with limits and their properties in calculus.
  • Knowledge of polynomial expressions and their behavior as n approaches infinity.
  • Basic proficiency in mathematical notation and manipulation.
NEXT STEPS
  • Study the application of the Ratio Test in various series convergence scenarios.
  • Learn about other convergence tests such as the Root Test and Comparison Test.
  • Explore the behavior of polynomial functions in limits, particularly $$\lim_{n\to\infty}\frac{(n+1)^{k}}{n^{k}}$$.
  • Investigate the implications of convergence in the context of power series and their radius of convergence.
USEFUL FOR

Students of calculus, mathematicians, and anyone involved in series analysis or convergence testing will benefit from this discussion.

Confusedalways
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I'm trying to determine if $$\sum_{n=1}^{\infty}\frac{{n}^{10}}{{2}^{n}}$$ converges or diverges.

I did the ratio test but I'm left with determining $$\lim_{{n}\to{\infty}}\frac{(n+1)^{10}}{2n^{10}} $$

Any suggestions??
 
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I would write the limit as:

$$L=\frac{1}{2}\lim_{n\to\infty}\frac{(n+1)^{10}}{n^{10}}=\frac{1}{2}\left(\lim_{n\to\infty}\left(1+\frac{1}{n}\right)\right)^{10}$$

Can you proceed?
 
Yes thanks!
 

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