Serious problem with centripetal force

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SUMMARY

The discussion focuses on calculating centripetal force for two different scenarios involving a rotating disc and a carousel. The first scenario involves a disc rotating at 0.5 revolutions per second with a block of mass 0.6 kg positioned 0.2 meters from the shaft, resulting in a centripetal force of 1.2 N. The second scenario involves a carousel with a chain length of 1.0 meter and a mass of 1.0 kg, where the calculated centripetal force is 1.9739 N, which contradicts the expected value based on the radius of 1.06 m. The confusion arises from the terminology used, specifically the term "rates per second," which was clarified to mean "revolutions per second."

PREREQUISITES
  • Understanding of centripetal force calculations using the formula Fc = mrw²
  • Familiarity with angular velocity and its conversion from revolutions per second to radians per second
  • Basic knowledge of trigonometric functions, particularly sine, for calculating angles
  • Ability to interpret physical scenarios involving rotational motion
NEXT STEPS
  • Study the derivation and applications of the centripetal force formula, Fc = mrw²
  • Learn about angular velocity conversions, specifically between revolutions per second and radians per second
  • Explore the effects of different radii and angles on centripetal force in various physical systems
  • Investigate the role of tension in chains and ropes in rotational dynamics
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Students studying physics, particularly those focusing on mechanics and rotational motion, as well as educators looking for examples of centripetal force calculations.

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Homework Statement



The soluble problem We have a disc, horisontal, which is rotating 0.5 revolutions per second. A block is placed on this disc with the mass 0.6 kg and 0.2 meters from the shaft. First, I convert 0.5 rates per second to T = 2 seconds. w = 2∏/2 --> w = ∏ --> m = 0.6 kg --> r = 0.2 meters

Fc = (0.6)(0.2)(∏)^2 --> Fc = 1.184352528 N --> Fc = 1.2 N

This is correct according to facit. So easy, but I just wanted to show how different this is in comparism to the coming one.
The insoluble problem A carousel, where the distance between centre and attachment to chain is 0.8 meters, the chain is 1.0 meter long and weight in the chain 1.0 kg. T = 4.0 s. Now, centripetal forces is asked, and I do the same as above: w = 2∏/4 --> w = ∏/2

Fc = (1.0)(0.8)(∏/2)^2 --> Fc = 1.97392088 N

This is according wrong according to:

http://www.walter-fendt.de/ph14d/karussell.htm

Even though the latter is hanging in a chain, the horizontal force should be the same; but resulting different. In Walter Fendt, they have found out that the radius is 1.06 m (0.8 + 0.26). The angle is unknown, but they have through 0.26 m counted this: sin a = 0.26/1.00 --> a = 15.

Homework Equations



Fc = mrw^2

w = 2∏/T


What have I missed?
 
Last edited:
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What does 'rates per second' mean? Is it supposed to be 'radians per second' or 'revolutions per second'?
 
SteamKing said:
What does 'rates per second' mean? Is it supposed to be 'radians per second' or 'revolutions per second'?


It was supposed to mean "revolutions per seconds". In fact, I have always believed that RPM on the motorcycle and cars meant rate per minute, but I did just learn that it means revolutions per minute. English is my second language.
 

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