OhMyMarkov
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Is $F^{-1}(F(E))\cap E=E$?
Thanks!
Thanks!
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The discussion centers on the mathematical concept of set equality involving a function \( F \) and its inverse \( F^{-1} \). It establishes that for any set \( E \), the relationship \( E \subseteq F^{-1}(F(E)) \) holds true. The participants confirm that the intersection \( F^{-1}(F(E)) \cap E \) equals \( E \), reinforcing the foundational properties of functions and their inverses in set theory.
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OhMyMarkov said:Is $F^{-1}(F(E))\cap E=E$?
Plato said:It is always the case that $E\subseteq F^{-1}(F(E))$