- #1
DorumonSg
- 64
- 0
I have this question but I don't get it at all. Here goes:
Let X be {x, y, z}
P(X) is the power set.
For all Y,Z is an element of P(X), Y R Z where The number of elements in Y intersect Z is 1.
So I worked out P(X) to be:
{(null), (x), (y), (z), (x,y), (x,z), (y,z)}
Then I don't get the next line, how can the number of elements of Y intersect Z be 1 if all members of Y and Z are elements of P(X)? Isn't Y = Z?
Let X be {x, y, z}
P(X) is the power set.
For all Y,Z is an element of P(X), Y R Z where The number of elements in Y intersect Z is 1.
So I worked out P(X) to be:
{(null), (x), (y), (z), (x,y), (x,z), (y,z)}
Then I don't get the next line, how can the number of elements of Y intersect Z be 1 if all members of Y and Z are elements of P(X)? Isn't Y = Z?