ship arrives from the Atlantic to the Baltic sea. How much does the draft of the ship deepen due to the saltyness of the water...
density of atlantic water = 1027kg/m^3
density of baltic water = 1005kg/m^3
at these depths the crosssectional area of the ship can be assumed to be 4000m^2
ship and cargo mass = 10000 metric tons
N= ρ V g
The Attempt at a Solution
I have no idea what ship draft is. I have only once been on a ship in my life. I have no idea why the the cross-sectional area would be relevant in this problem.
But I decided to calculate the volumes of water, which the ship displaces in atlantic,
And then displaces in the baltic.
I think those volumes will be different because water density changes.
Natlantic = ρatlantic x Vatlantic x g
Vatlantic= 9737, 0983 m^3
Nbaltic = ρbaltic x Vbalticx g
Vbaltic = 9950,2487 m^3
I was later on thinking that maybe if I were to take all the water into a huge box
Then you could divide the displaced water volumes, by the area
Therefore you end up with height ( I think) Or something to this effect could be done.
If this is calculated so, then the difference between the heights of the displaced water is
(9950,2487m^3) / 4000m^2 = 2,4875 m = height baltic
9737,0983 m^3 / 4000m^2= 2,4342 m height atlantic.
calculate Δheight = 0,0533m
the deepening effect ought to be about 5,3 cm
please notify whether or not errors of understanding of judgement were made.