1. The problem statement, all variables and given/known data ship arrives from the Atlantic to the Baltic sea. How much does the draft of the ship deepen due to the saltyness of the water... density of atlantic water = 1027kg/m^3 density of baltic water = 1005kg/m^3 at these depths the crosssectional area of the ship can be assumed to be 4000m^2 ship and cargo mass = 10000 metric tons g= 9,81m/s^2 2. Relevant equations N= ρ V g G=mg 3. The attempt at a solution I have no idea what ship draft is. I have only once been on a ship in my life. I have no idea why the the cross-sectional area would be relevant in this problem. But I decided to calculate the volumes of water, which the ship displaces in atlantic, And then displaces in the baltic. I think those volumes will be different because water density changes. Natlantic = ρatlantic x Vatlantic x g Vatlantic= 9737, 0983 m^3 Nbaltic = ρbaltic x Vbalticx g Vbaltic = 9950,2487 m^3 I was later on thinking that maybe if I were to take all the water into a huge box Then you could divide the displaced water volumes, by the area Therefore you end up with height ( I think) Or something to this effect could be done. If this is calculated so, then the difference between the heights of the displaced water is (9950,2487m^3) / 4000m^2 = 2,4875 m = height baltic 9737,0983 m^3 / 4000m^2= 2,4342 m height atlantic. calculate Δheight = 0,0533m the deepening effect ought to be about 5,3 cm please notify whether or not errors of understanding of judgement were made.