Buoyancy and Density Archimedes

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SUMMARY

This discussion focuses on buoyancy and density calculations involving a 300 kg object placed on ice. The required volume of ice to keep the object fully above water is determined to be 3.75 m³. When the ice is half the size, approximately 6% of the object remains above water due to its density of 0.94 g/cm³. The calculations confirm that when the ice melts, the volume of the object above water is 0.01914 m³, validating the principles of buoyancy and density.

PREREQUISITES
  • Understanding of buoyancy principles
  • Knowledge of density calculations
  • Familiarity with the equation V = m/p
  • Basic physics concepts related to mass and volume
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  • Learn about the effects of temperature on ice density
  • Explore real-world applications of buoyancy in engineering
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Students studying physics, educators teaching buoyancy concepts, and anyone interested in the practical applications of density and buoyancy in real-world scenarios.

Koborl
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Homework Statement



1. a 300kg object is placed upon a block of ice what volume of ice is needed to keep the object fully above water.

2. if the object density is .94gcm ^-3 what volume of the object remains above water on ice half the size.

3. What volume of the object remains above water when the ice is fully melted.

p(water) = 1gcm^-3
p(ice) = 0.92 gcm^-3

Homework Equations

B = mfg
V = m/p

The Attempt at a Solution



1.
v= volume of water displaced

(denstiy of water)1000 kg/m^3* v = 300(weight of object)+ (denstiy ice)920 kg/m^3 *v
80 kg/m^3 v = 300
v = 3.75 m^3

2. ?

3. 6% of the object remains above water because buoyancy is .94 and water is 1?

V = m/p

p = 0.94 g/cm3
M = 300 kg = 300000g
V = 0.31914893617021 m^3

V above water = .01914m^3

I'm fairly sure I've got question 3 all wrong though :(
 
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Please respond.
 
Koborl said:
p = 0.94 g/cm3
M = 300 kg = 300000g
V = 0.31914893617021 m^3

V above water = .01914m^3

I'm fairly sure I've got question 3 all wrong though :(

No, it is correct. V(immersed)ρ(water)=mass of object

ehild
 

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