Shooting a block up an incline - work energy

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Homework Help Overview

The problem involves a block being shot up an incline using a spring gun. The block's motion is influenced by the spring constant, the incline's angle, and the coefficient of kinetic friction. Participants are tasked with finding the distance the block travels along the incline after exiting the gun, expressed in terms of various physical parameters.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss energy conservation equations and the role of friction in the system. There are attempts to derive expressions for the distance traveled by the block, with some questioning the inclusion of friction during the block's time in the gun.

Discussion Status

There are multiple approaches being explored, with participants providing different energy equations. Some participants express confusion about the complexity of the resulting expressions and question the assumptions made in their derivations. No consensus has been reached on the correct formulation.

Contextual Notes

Participants note the importance of considering energy contributions from both the spring and gravitational forces, as well as the effects of friction. There is an acknowledgment of potential missing components in the energy equations.

ph123
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A block of mass m is placed in a smooth-bored spring gun at the bottom of the incline so that it compresses the spring by an amount x_c. The spring has spring constant k. The incline makes an angle theta with the horizontal and the coefficient of kinetic friction between the block and the incline is mu. The block is released, exits the muzzle of the gun, and slides up an incline a total distance L.

Find L, the distance traveled along the incline by the block after it exits the gun. Ignore friction when the block is inside the gun. Also, assume that the uncompressed spring is just at the top of the gun (i.e., the block moves a distance x_c while inside of the gun). Use g for the magnitude of acceleration due to gravity.
Express the distance L in terms of mu, theta, g, x_c, m, and k.


My energy equation is as follows:

0.5k(x_c)^2 = 0.5mv^2 + (mu)mg((x_c) + L)cos(theta)
0.5k(x_c)^2 = (mu)mg((x_c) + L)cos(theta)
[0.5k(x_c)^2]/[(mu)mgcos(theta)] = x_c + L
L = [0.5k(x_c)^2]/[(mu)mgcos(theta)] - x_c

I know you have to add X_c to L to find the total distance the block is moved by the spring, and I really don't understand why this is wrong. Anyone know?
 
Last edited:
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It seems to me that you have included friction while the block is in the gun, if I am reading that correctly.
But anyway, this travels up an incline, did you get all the energy associated with your system?
 
0.5k(x_c)^2 = mg((x_c) + L)sin(theta) + (mu)mgLcos(theta)

I guess I forgot the y component

But that leaves me with:

L=[k(x_c)^2 - 2mg(x_c)sin(theta)]/[2mg[(mu)cos(theta) + sin(theta)]]

Which seems to me way too complicated an expression.
 
ph123 said:
0.5k(x_c)^2 = mg((x_c) + L)sin(theta) + (mu)mgLcos(theta)

I guess I forgot the y component

But that leaves me with:

L=[k(x_c)^2 - 2mg(x_c)sin(theta)]/[2mg[(mu)cos(theta) + sin(theta)]]

Which seems to me way too complicated an expression.
lol, that is not too bad of an expression!
*edit* - the first equation looks okay to me, I didnt check your algebra in the next step.
 

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