1. The problem statement, all variables and given/known data A cannon 60m horizontally from the base of a 25m cliff is fired with a speed of 32.6m/s at an angle of 43 degrees above the horizontal towards the cliff. How far does the shell land past the edge of the cliff assuming its elevation is constant 2. Relevant equations y = v0yt -.5gt^2 x= v0xt 3. The attempt at a solution I plug in the to the first equation 25m = 32.6sin(43)t -4.9t^2 and the quadratic formula gives me two answers: 2.46s and 2.06s so I plug this into the second equation giving me distances of 49.0m and 58.6 which seems to mean that the cannonball does not actually clear the cliff...but my online how system is asking for an answer.