Short Exact Sequence: Explaining C = B/A

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SUMMARY

The discussion centers on the short exact sequence represented as 0 → A → B → C → 0, where the mappings from A to B are injective and from B to C are subjective. The relationship C = B/A is established through the natural mapping of B to the quotient B/A, as detailed in the referenced Wikipedia article on exact sequences. The conclusion drawn is that C is indeed equivalent to the quotient B/A, confirming the properties of exact sequences in algebraic topology.

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  • Familiarity with injective and subjective mappings
  • Knowledge of quotient structures in mathematics
  • Basic concepts of homological algebra
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http://en.wikipedia.org/wiki/Exact_sequence
Let's look at the following short exact sequence:
0-->A-->B-->C-->0.

Since the sequence is exact, the mapping from A-->B will be invective and the mapping B-->C will be subjective. The wikipedia article says that we can think of the mapping A-->B as a mapping that embeds A into B. It also says that we can think of the mapping from B-->C as the natural mapping of B-->B/A, and that B/A = C.Can anyone explain why this is? Why must C = B/A?
EDIT: I understand now, thanks anyone PF
:P
 
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