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0->A-> B -> 0

; A,B Z-modules, be a short exact sequence. It follows A is isomorphic with B.

. We have that tensor product is

right-exact , so that, for a ring R:

0-> A(x)R-> B(x)R ->0

is also exact. STILL: are A(x)R , B(x)R isomorphic?

I suspect no, if R has torsion. Anyone have an example of

A(x)R , B(x)R non-isomorphic, but A,B isomorphic? Thanks.

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# Short Exact Sequences and at Tensor Product

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