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digi99
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I had 1 year ago a little discussion with DaleSpam about the short Lorentz derivation (triangle) if a photon alone can be seen as a light beam.
1) The long Lorentz derivation seems me correct, so no discussion about that
2) For the short Lorentz derivation with the triangle (c.t , v.t and c.t’) I had my doubts, but who am I, so maybe correct too
3) Now I have because of 2 the next problem, an equal idea, maybe I just don’t see it:
Consider a light source with speed V along a straight line and the source emitted only one photon as in 2).
Start-------t,A--------source with speed V------------------------t’,B----------------------photon
t = time t in inertial system s1
A = distance between startpoint and source (having speed V)
t’ = time t’ in inertial system s2 (rest system of source)
B = distance between source and photon
It’s like the triangle from 2 but in flat form (photon horizontally traveling in stead of vertically in s2).
The observer in s1 sees the photon from the start point in his/her inertial system s1 with speed C and time t.
An observer In system s2 sees the photon with time t’ and C.
So an observer in s1 may write: c.t (= A + B) = v.t (= A) + c.t’ (= B) or (c-v).t = c.t’, this gives not Lorentz but t’ = (1 – v/c).t
What I am doing wrong here (very curious) ?
1) The long Lorentz derivation seems me correct, so no discussion about that
2) For the short Lorentz derivation with the triangle (c.t , v.t and c.t’) I had my doubts, but who am I, so maybe correct too
3) Now I have because of 2 the next problem, an equal idea, maybe I just don’t see it:
Consider a light source with speed V along a straight line and the source emitted only one photon as in 2).
Start-------t,A--------source with speed V------------------------t’,B----------------------photon
t = time t in inertial system s1
A = distance between startpoint and source (having speed V)
t’ = time t’ in inertial system s2 (rest system of source)
B = distance between source and photon
It’s like the triangle from 2 but in flat form (photon horizontally traveling in stead of vertically in s2).
The observer in s1 sees the photon from the start point in his/her inertial system s1 with speed C and time t.
An observer In system s2 sees the photon with time t’ and C.
So an observer in s1 may write: c.t (= A + B) = v.t (= A) + c.t’ (= B) or (c-v).t = c.t’, this gives not Lorentz but t’ = (1 – v/c).t
What I am doing wrong here (very curious) ?
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