Short question: Spontaneous emission from Feynman diagrams?

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SUMMARY

The discussion centers on calculating the Einstein coefficient for spontaneous emission in two-level atoms using Feynman diagrams. The user, blue2script, seeks clarification on whether it is feasible to derive this coefficient by incorporating a proton's energy levels influenced by an external magnetic field into the Lagrangian. The conversation confirms that after establishing the Feynman rules, one can indeed compute the decay rate for a proton in an excited state.

PREREQUISITES
  • Understanding of Feynman diagrams and their application in quantum mechanics.
  • Knowledge of the Einstein coefficient and its relevance in spontaneous emission.
  • Familiarity with Lagrangian mechanics and its role in particle physics.
  • Basic concepts of quantum states and energy levels in atomic systems.
NEXT STEPS
  • Study the derivation of the Einstein coefficient in quantum mechanics.
  • Learn about Feynman rules and their application in calculating decay rates.
  • Explore Lagrangian formulations in the context of quantum field theory.
  • Investigate the effects of external magnetic fields on atomic energy levels.
USEFUL FOR

This discussion is beneficial for physicists, particularly those specializing in quantum mechanics and particle physics, as well as students seeking to understand the application of Feynman diagrams in calculating atomic emission processes.

blue2script
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Hey all,
I am just wondering if one can directly calculate the Einstein coefficient in spontaneous emission of, say, two-level atoms through feynman diagrams? I searched for sources in google but could not find anything.

Thanks a lot for an answer!

Wit best regards,
blue2script
 
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Maybe I can render the question more precisely: Given a proton in an outer magnetic field I get two energy levels depending on the direction of spin. I can plug the outer field into the Lagrangian. After determing the feynman rules I should be prepared to calculate the decay rate of a proton in the upper energy state.

Am I right?
 

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