Should we think a free particle as a particle in an infinitely big box?

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Discussion Overview

The discussion revolves around the conceptual analogy between a free particle and a particle confined within an infinitely large box. Participants explore the implications of boundary conditions on momentum expectation values and the nature of wave functions in different spatial configurations.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant notes that the momentum expectation of a particle in a finite box is zero due to equal probabilities of moving left and right, and questions whether a similar result holds for a free particle treated as being in an infinitely long box.
  • Another participant discusses the importance of boundary conditions, contrasting the hard-wall boundary conditions of a finite box with the periodic boundary conditions of a circular box, leading to different momentum expectations.
  • A third participant suggests that for a free particle, the concept of an infinitely large box does not impose a limit, implying that the particle's position uncertainty is infinite.
  • Another contribution argues against the assumption that energy eigenstates of a finite square well converge to those of a free particle, suggesting instead that a particle in an infinite box can be viewed as a superposition of momenta due to reflections at infinity.

Areas of Agreement / Disagreement

Participants express differing views on the implications of boundary conditions for momentum expectations and the relationship between finite and infinite boxes. There is no consensus on whether the analogy between a free particle and a particle in an infinitely large box is valid.

Contextual Notes

The discussion highlights the dependence of results on boundary conditions and the nature of wave functions, with unresolved questions regarding the transition from discrete to continuous energy states.

nathatanu0
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I've found that the momentum expectation of a particle inside an one dimensional finite box of length 'L' is '0'... we can say the probability of going right=that of the left... so sum up to zero. Now I calculate the same(<p>) for a free particle in one dimension if I think that free particle is not exactly free but kept inside an infinitely long box(L-->infinity)... the result should be the same... does that happen... does it make any sense to draw analogy between the two... ?? please help.

atanu
 
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This is a subtle question. For the finite box, I assume you required the wave function to vanish at the walls; in other words, you imposed the boundary conditions [itex]\psi(0)=0[/itex] and [itex]\psi(L)=0[/itex]. But there is another kind of finite box: a circle instead of a line-segment. Then the wave function is required to be periodic: [itex]\psi(x+L)=\psi(x)[/itex]. (Actually, you can have periodicity up to a phase instead,[itex]\psi(x+L)=e^{i\phi}\psi(x)[/itex], but I want to ignore that possibility.) In this case, you can have a free-particle wave function that has nonzero [itex]\langle p\rangle[/itex], such as [itex]\psi(x)=L^{-1/2}\exp(2\pi i n x/L)[/itex], where [itex]n[/itex] is an integer (positive, negative, or zero); then [itex]\langle p\rangle=2\pi\hbar n/L[/itex]. We could now consider the limit of [itex]L\to\infty[/itex]; if we also take [itex]n\to\infty[/itex], we end up with nonzero [itex]\langle p\rangle[/itex]. But for the hard-wall box, we would always get [itex]\langle p\rangle=0[/itex]. So the results depend on the boundary conditions, even for an infinite box.
 
it can be think as
for free particle [tex]\Delta[/tex]X=infinity
therefore, infinitely big box is not so big for free particle
 
There is no reason to suppose that the (discrete set of) energy eigenstates of the square well will tend to the (continuum of) energy eigenstates for a free particle, but it is possible to write a general state as a sum of energy eigenstates and have this sum tend to an integral, and take apart the sines into e^ i k x and e ^ - i k x to see that the particle in an infinitely large box is like a free particle which has reflected off of infinity and so is in a superposition of +k and -k momenta. Such is nonrelativistic QM!
 

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