Show that it is orthogonal to both u and v

[htk]

find u X v and show that it is orthogonal to both u and v.

u= 6k
v=-i + 3j + k

http://s763.photobucket.com/albums/xx275/trinhkieu888/?action=view&current=666.jpg

This is what I got from the picture, but my teacher said that I have one more step to do to show that they are orthogonal, I need to do uxv

uxw = (0*-18)+(0*-6)+(6*0)= ?

and also vxw=?

If both are zero, the vectors are orthogonal.

But my problem is I don't know how to find w. Can anyone please explain it to me? Thank you very much!

 

[LCKurtz]

find u X v and show that it is orthogonal to both u and v.

u= 6k
v=-i + 3j + k

http://s763.photobucket.com/albums/xx275/trinhkieu888/?action=view&current=666.jpg

This is what I got from the picture, but my teacher said that I have one more step to do to show that they are orthogonal, I need to do uxv

uxw = (0*-18)+(0*-6)+(6*0)= ?

and also vxw=?

If both are zero, the vectors are orthogonal.

But my problem is I don't know how to find w. Can anyone please explain it to me? Thank you very much!

uxw is a vector. Where are your i, j, k? I think you have it correct on your paper.

If you want to show uxw is orthogonal to u and v, remember that two nonzero vectors are orthogonal if their dot product is 0.

 

[njama]

Call the orthogonal vector w.

If two vectors are orthogonal then the angle between them is 90⁰

You can prove it using the dot product:

$$\mathbf{u} \cdot \mathbf{w} = 0$$

and

$$\mathbf{v} \cdot \mathbf{w} = 0$$

or finding cos(u,w) and cos(v,w) for the cross product (since you already find w).

 

[HallsofIvy]

Excuse me, but you first say "find u X v and show that it is orthogonal to both u and v" but then start talking about "u x w" and "v x w". Where did "w" come from? If you mean that w= u x v, then, as njama said, you want to look at the dot product of w with u and v, not the cross product. You do NOT, by the way, need to divide by ||u x v|| since the problem says nothing about a unit vector.