Show that killing vector field satisfies....

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SUMMARY

This discussion focuses on the properties of Killing vector fields in the context of General Relativity (GR). It establishes that a spacetime is stationary if and only if there exists a timelike Killing vector field, denoted as V. Additionally, it confirms that if spacetime is static, a timelike Killing vector field satisfying the condition V_{[\alpha}\nabla_\mu V_{v]}=0 exists. The discussion also addresses the implications of this condition, leading to the conclusion that the expression \nabla_\mu(|V|^n V_\nu)-\nabla_\nu(|V|^n V_\mu)=0 holds true, where |V|^2=V_a V^a and n is an integer.

PREREQUISITES
  • Understanding of General Relativity concepts, specifically Killing vector fields
  • Familiarity with metric components and their derivatives in GR
  • Knowledge of antisymmetrization in tensor calculus
  • Proficiency in using Christoffel symbols and their relation to metric derivatives
NEXT STEPS
  • Study the properties of Killing vector fields in more depth, focusing on their role in symmetries of spacetime
  • Learn about the implications of static and stationary spacetimes in General Relativity
  • Explore the use of the product rule in tensor calculus, particularly in the context of GR
  • Investigate the relationship between Killing vectors and conserved quantities in physical systems
USEFUL FOR

This discussion is beneficial for students and researchers in theoretical physics, particularly those specializing in General Relativity and the mathematical foundations of spacetime symmetries.

Augbrah
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I'm trying to do past exam papers in GR but there are some things I don't yet feel comfortable with, so even though I can do some parts of the question I would be very happy if you could check my solution. Thank you!

1. Homework Statement

Spacetime is stationary := there exists a coord chart with a timelike coordinate x^0 such that metric components \partial_0 g_{\mu \nu} = 0.
Spacetime is static := there exists a coord chart such that \partial_0 g_{\mu \nu} = 0 and g_{0i} = 0

i) [Done] Show that spacetime is stationary if and only if there exists a timelike Killing vector field V.
ii) [Done] Show that if spacetime is static, there exists a timelike Killing vector field satisfying V_{[\alpha}\nabla_\mu V_{v]}=0
iii) Let V be timelike Killing vector field with V_{[\alpha}\nabla_\mu V_{v]}=0. Show that this condition implies \nabla_\mu(|V|^n V_\nu)-\nabla_\nu(|V|^n V_\mu)=0 Where |V|^2=V_a V^a and n is integer which should be determined.

Homework Equations


Killing vector field V satisfies \nabla_\mu V_\nu + \nabla_\nu V_\mu = 0

The Attempt at a Solution


i) I have done this part. For timelike V^\mu we can find an inertial frame s.t. V^\mu = \delta^\mu_0. Then V_\mu = g_{\mu 0}. Hence \nabla_\mu V_\nu + \nabla_\nu V_\mu =...=\partial_0 g_{\mu\nu}, by expressing Christoffel symbols as partial derivatives of a metric other derivatives nicely cancel.

So we proved that timelike Killing V ⇔ \partial_0 g_{\mu\nu}=0.

ii) If spacetime is static, it is also stationary, so we already know from i) there must exist timelike Killing V, just need to show it satisfied the equation (right?). By expanding antisymmetrization we have
V_{\alpha}(\nabla_\mu V_{\nu} - \nabla_\nu V_{\mu}) + \text{(other 2 cyclicly permuted pairs)}=0 Studying the first term and using same identification V_\mu = g_{\mu 0} and as before remembering that for static spacetime g_{0i} = 0 as well as \partial_0 g_{\mu \nu} = 0 we get:
V_{\alpha}(\nabla_\mu V_{\nu} - \nabla_\nu V_{\mu}) = g_{\alpha 0} (\partial_\mu g_{\nu 0} - \partial_\nu g_{\mu 0}) = 0

Same procedure for other two terms and total sum is 0.

iii) Besides product rule I did not got far. Any suggestions?
 
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You should probably how far you got with part (iii).
 
I might be missing something but I don't think what you wrote at the end of part ii) is correct. If you put μ=i and ν=0 this is not zero but equal to g_{\alpha 0}\partial_i g_{00} which is not necessarily zero
You really need to antisymmetrise in order to get zero identically
 
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