Show That Vector Squared is Equal to 12r

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Homework Help Overview

The problem involves demonstrating that the Laplacian of the cube of the magnitude of a vector is equal to a specific expression. The subject area includes vector calculus and differential operators.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the meaning of the Laplacian operator and its application to the problem. There is uncertainty about the concept of squaring a vector and the implications of the Laplacian in this context.

Discussion Status

Some participants have provided definitions and clarifications regarding the Laplacian and the magnitude of the vector. There is acknowledgment that understanding index notation could simplify the problem, but it appears that not all participants are familiar with it.

Contextual Notes

There is a mention of the potential complexity of the problem, indicating that it may require significant work to resolve. The discussion also highlights a possible gap in knowledge regarding the Laplacian and index notation among participants.

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Homework Statement



[tex]\vec r = <x, y, z>, r = \left |\vec r \right |[/tex]

Show that [tex]\nabla ^2 r^3 = 12r[/tex]


Homework Equations



I don't understand how a vector can be squared. What does [tex]\nabla ^2[/tex] mean?
 
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del^2 is d^2/dx^2+d^2/dy^2+d^2/dz^2. It's the sum of the second derivatives. It's the laplacian.
 
Like Dick said nabla squared is called the laplacian. Don't forget that r=sqrt{x^2+y^2+z^2}, This problem is going to be a lot of work.
 
Do you know index notation? This is a 3-liner if you know it. Although come to think of it if you haven't seen the Laplacian, then you probably don't.
 

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