Show the hex representation of MIPS instructions

  1. Hey all
    1. The problem statement, all variables and given/known data
    Here i want to translate them and show the hex representation of these instructions:
    1)add $t0, $t0, $zero
    2)lw $t2, 16($s3)

    2. Relevant equations
    3. The attempt at a solution
    eg. 2)
    lw | $s3 | $t2 | 16
    I-TYPE

    then translate the assembly code:
    35 | 19 | 10 | 16

    The solution is 0x8E6A0010
    But i 've no idea how the answer has been reached... Any help?
    Thank's a lot
     
    Last edited: May 22, 2011
  2. jcsd
  3. What is the context of this question? Should you be able to answer it on a test or is it a homework problem meant to familiarize you with your assembler? I would write the code, compile it, and view the answer by stepping through the code.
     
  4. lewando

    lewando 1,077
    Gold Member

    Looks like you have decomposed the assembly instruction correctly:

    3510 = instruction
    1910 = s
    1010 = t
    1610 = C

    Convert the base-10 values that you obtained into binary. Then group your binary results into the following I-type format:
    [iiiiiiss] [sssttttt] [CCCCCCCC] [CCCCCCCC]

    (use 6-bits of your instruction result, 5-bits of s, 5 of t, 16 bits of C, zero-padding as needed)

    Then convert each 8-bit group to its hexadecimal equivalent.
     
  5. thank you so much! cheers ;)
     
  6. Could you please show me the way to convert hex value 0x8E6A0010 to decimal?
     
    Last edited: May 23, 2011
  7. The nth digit corresponds to how many b^n's there are, starting at n = 0, where b is the base (16 here).

    0*16^0 + 1*16^1 + 0*16^2 + ... + 8*16^7
     
  8. Oo yeah... thank's man ;)
     
  9. No problem. That method works for converting any integer of any base into base 10 (you can even convert base 10 into base 10 with it).

    e.g.
    10110 base 2 = 0*2^0 + 1*2^1 + 1*2^2 + 0*2^3 + 1*2^4 = 2 + 4 + 16 = 22
     
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